WebJan 16, 2024 · Illustrative Example Of Meyerhof Bearing Capacity Equation With Inclined Load. A continuous foundation is 1.5 m wide and is founded at a depth of 1.5 m in a deep layer of sand of unit weight 18.5kN/m3. Determine the ultimate bearing capacity of the foundation if the soil strength parameters are c' = 0 and ft = (i) 35°, (ii) 30°. WebA rectangular footing of 1.5x2.0 m on stiff clay (0= 0) is subjected to an inclined load as shown in figure below. What is the factor of safety against shear failure ; ( Use Meyerhof s Equation) !B = 30° %3D G.S. 180 kN D; =1.5m y = 20 kN/m² C = 80 kPa B = 1.5mn 4 m W.T.
Analysis of Strip Footing using PLAXIS 2D - Research and …
WebINTRODUCTION Footings of retaining walls, abutments, industrial machines, and portal framed buildings are not onlysubjected to vertical or inclined loads but also to moments. Moments on the foundation base are mainly caused by … Webprojection on one side such that it is an integral part of the footing it is called angle shape footing. Construction of footing projection at the base of the footing, confining the … how do you make a diamond pickaxe
Answered: Problem 5 A strip footing shown has an… bartleby
WebOct 20, 2006 · im also looking at a spread footing with bored piers anchors.. anyway, one more shot.. how much load factor should be given to the prestressing load ( deadload factor =1.2, live load =1.5 ) Im inclined to use 1.2 since the load is controlled and will not vary that much.. any thoughts on this? Cheers! WebA strip footing shown has an inclined load acting at an eccentricity shown. Cohesion = 18 kPa, Unit weight of Soil = 15.82 kN/m³, Angle of internal friction = 28 degrees, and Depth of foundation = 1.2m. Calculate the following A) Ultimate Bearing Capacity per meter length of the footing B) Ultimate Load per meter length of the footing 0.15 m Quei) WebThe term D is in radians B Note 2: The depth and shape factors for inclined loads should be set to 1. For loading inclined in the direction of the width 6,0 = 90 in Fig. 9.9 (d). tan ng = (2+ (2+)/ (1+). For loading inclined in the direction of the length L, 6 = 0in Fig.990), n = m = ( = (2+)/ (1+) For other loading conditions, n = nl cos+nB sin how do you make a desktop icon for a url